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The password is sent to the reader in encrypted form
first three bytes XOR mask 55AA55
next 3 bytes - unknown (((
encrypted pass -> decrypted pass
F50BF74D4287 -> A0A1A2A3A4A5
E51BE7510ECB -> B0B1B2B3B4B5
AA55AA284343 -> FFFFFFFFFFFF
44BB44893434 -> 111111111111
778877AFADAD -> 222222222222
55AA556B4343 -> 000000FFFFFF
AA55AAD7BCBC -> FFFFFF000000
00FF00FF1616 -> 555555555555
FF00FF43E9E9 -> AAAAAAAAAAAA
55AA5594BCBC -> 000000000000
55AA5594BCBD -> 000000000001
55AA5595BCBD -> 000000010001
55AA5594BCBE -> 000000000002
55AA5596BCBE -> 000000020002
55AA5594BCBF -> 000000000003
55AA5594BCB8 -> 000000000004
55AA5594BCB9 -> 000000000005
55AA5594BCBA -> 000000000006
55AA5594BCBB -> 000000000007
55AA5594BCB4 -> 000000000008
55AA55000000 -> 00000094BCBC
55AA55FFFFFF -> 0000006B4343
55AA5494BCBC -> 000001000000
55AA5794BCBD -> 000002000000
55AA5694BCBD -> 000003000000
55AA5194BCBF -> 000004000000
55AA5094BCBF -> 000005000000
55AA5394BCBE -> 000006000000
54AA559479BC -> 010000000000
57AA559536BC -> 020000000000
51AA5597A8BC -> 040000000000
5DAA559294BC -> 080000000000
45AA5598ECBC -> 100000000000
75AA558C1CBC -> 200000000000
15AA55A5FCBC -> 400000000000
D5AA55F63CBC -> 800000000000
Last edited by Sentinel (2015-11-13 20:54:01)
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Do you have the UIDs connected with those keys?
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It is a protocol between the reader and PC software inhova. in software exhibited the default password, and in the COM port (sysinternals/portmon) you can see the encrypted password. Then reader recovers password.
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4th, 5th and 6th bytes are related to 1st 3bytes values. Not at home To study it further today.
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They are first xored with 94BCBC but then xored with some result of a calc on first 3 bytes. Not enough data to identify calc. IMO.
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not enough time to set a logical 1 of all charges..In the near future following the results of research
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